Given a vector of n x n elements
0. simplify vector from game object to vector of unsigned int id:
GameObject:
id
texture 
position
...
-> id
we get a vector: 
{
    0 1 2
    2 1 0
    1 2 0
}
1. split the vector into vertical and horizontal 
vertical: 
calculate square root of vector size -> thats the length of single row and column
    a) split horizontaly
    get first n elements -> thats first vertical
    then get second n elements -> thats second vertical
    ...
    in the end we get 3 vectors:
    { 0, 1, 2}
    { 2, 1, 0}
    { 1, 2, 0}
    b) split vertically
        get first element [0]
            add "n" elements
            get second column [n] (in our case 3)
            repeat until number of column + n < n^2
        increment first element by 1
        go to loop start if first element <= n (3)
    in the end we get 3 vectors
    { 0, 2, 1 }
    { 1, 1, 2 }
    { 2, 0, 0}
Matching logic:
1. Find matches 
    a) Vertical
    t   t   t
    t   t   t
    t   t   t
        t   t
            t
        I)
            Since we splited our vectors into vectors of ids we made our job much easier
            count = 1
            take first element 
            take second element
            check if first == second
            if yes count += 1 
            if no count = 1
            take third element
            check if second == third
            if yes count += 1
            if no = 1
            if count >= 3
            matchesVector.push_back(0, 1, 2)
            if count == 1
            
    b) horizontal
    t t t
    t t t t
    t t t t t