WUT_Computer_Science/NotProgramming/ENUME/projectC/task1.m

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Mathematica
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2022-01-07 22:44:18 +01:00
function task1(polynomialDegree)
for currentPolynomialDegree = 0 : polynomialDegree
dataPoints = functionDataPoints();
% obtain LSPSolutions of approximating polynomial
[LSPSolutions, error, conditionNumber] = approximate(dataPoints, currentPolynomialDegree);
displayInfo(currentPolynomialDegree, error, conditionNumber);
plotGraph(currentPolynomialDegree, dataPoints, LSPSolutions)
end
end
function displayInfo(currentPolynomialDegree, error, conditionNumber)
disp("Current Polynomial Degree:");
disp(currentPolynomialDegree);
disp("Error: ");
disp(error);
disp("Condition number of Gram's Matrix: ");
disp(conditionNumber);
end
function plotGraph(currentPolynomialDegree, dataPoints, LSPSolutions)
figure;
grid on;
hold on;
plotDataPoints(currentPolynomialDegree, dataPoints);
plotApproximation(dataPoints, LSPSolutions);
hold off;
end
function plotDataPoints(currentPolynomialDegree, dataPoints)
title(['Polynomial approximation of the funtion using: ', num2str(currentPolynomialDegree), ' degree']);
scatter(dataPoints(:, 1), dataPoints(:, 2), 72, 'x');
end
function plotApproximation(dataPoints, LSPSolutions)
x = dataPoints(1):0.05:dataPoints(end, 1);
y = valueApproximationAtx(LSPSolutions, x);
plot(x, y);
end
% find the approximating polynomial of the given degree
function [LSPSolutions, error, conditionNumber] = approximate(dataPoints, polydeg)
% initialize A matrix
A = zeros(size(dataPoints, 1), polydeg + 1);
A = calculateACells(dataPoints, A);
LSPSolutions = solveLSP(A, dataPoints);
% Calculate error of solution
error = norm(dataPoints(:, 2) - A * LSPSolutions);
% Calculate condition number of Gram's matrix
GramsMatrix = A' * A;
conditionNumber = cond(GramsMatrix);
end
function Matrix = calculateACells(dataPoints, Matrix)
for row = 1 : size(Matrix, 1)
for column = 1 : size(Matrix, 2)
Matrix(row, column) = dataPoints(row, 1) ^ (column - 1);
end
end
end
function solutions = solveLSP(Matrix, dataPoints)
[Q, eqsys, invqtq] = QRDecomposition(Matrix);
eqsys(:, end + 1) = invqtq * Q' * dataPoints(:, 2);
solutions = backSubstitution(eqsys);
end
% evaluate the value of an approximation at the given x
function arrayOfValues = valueApproximationAtx(LSPSolutions, arrayOfArguments)
arrayOfValues = zeros(1, size(arrayOfArguments, 2));
arrayOfValues = calculateArrayofValues(arrayOfArguments, arrayOfValues, LSPSolutions);
end
function arrayOfValues = calculateArrayofValues(arrayOfArguments, arrayOfValues, LSPSolutions)
for x = 1 : size(arrayOfArguments, 2)
for i = 1 : size(LSPSolutions, 1)
arrayOfValues(x) = arrayOfValues(x) + LSPSolutions(i) * arrayOfArguments(x) ^ (i - 1);
end
end
end